$A$ satellite of mass $m$ revolving in a circular orbit of radius $r$ around the Earth has kinetic energy $E$. Then its angular momentum will be

Write an equation of total energy of a satellite. Why is the total energy of a satellite negative?

An astronaut takes a ball of mass $m$ from Earth to space. He throws the ball into a circular orbit about Earth at an altitude of $318.5 \ km$. From Earth's surface to the orbit,the change in total mechanical energy of the ball is $x \frac{GM_e m}{21 R_e}$. The value of $x$ is (take $R_e = 6370 \ km$).

The figure shows the variation of energy with the orbit radius of a body in circular planetary motion. Find the correct statement about the curves $A, B$ and $C$.

Let the kinetic energy of a satellite be $x$,then its time of revolution $T$ is proportional to ..............

Given below are two statements:
Statement $I:$ If $E$ be the total energy of a satellite moving around the earth,then its potential energy will be $\frac{E}{2}$.
Statement $II:$ The kinetic energy of a satellite revolving in an orbit is equal to the half the magnitude of total energy $E$.
In the light of the above statements,choose the most appropriate answer from the options given below.