Reduce the equation $y-2=0$ into the normal form $x \cos \omega + y \sin \omega = p$. Find the perpendicular distance from the origin $(p)$ and the angle between the perpendicular and the positive $x$-axis $(\omega)$.
- A$p=2, \omega=90^{\circ}$
- B$p=1, \omega=90^{\circ}$
- C$p=2, \omega=0^{\circ}$
- D$p=1, \omega=0^{\circ}$
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