Read the following two statements below carefully and state, with reasons, if it is true or false.
$(a)$ The Young’s modulus of rubber is greater than that of steel;
$(b)$ The stretching of a coil is determined by its shear modulus.
(a) False
(b) True
For a given stress, the strain in rubber is more than it is in steel.
Young's modulus, $Y=\frac{\text { Stress }}{\text { Strain }}$
For a constant stress: $Y \propto \frac{1}{\text { strain }}$
Hence, Young's modulus for rubber is less than it is for steel.
Shear modulus is the ratio of the applied stress to the change in the shape of a body. The stretching of a coil changes its shape. Hence, shear modulus of elasticity is involved in this process.
A thick rope of density $\rho$ and length $L$ is hung from a rigid support. The Young's modulus of the material of rope is $Y$. The increase in length of the rope due to its own weight is
A mild steel wire of length $1.0 \;m$ and cross-sectional area $0.50 \times 10^{-2} \;cm ^{2}$ is stretched, well within its elastic limit, horizontally between two pillars. A mass of $100 \;g$ is suspended from the mid-point of the wire. Calculate the depression at the midpoint.
A uniform heavy rod of mass $20\,kg$. Cross sectional area $0.4\,m ^{2}$ and length $20\,m$ is hanging from a fixed support. Neglecting the lateral contraction, the elongation in the rod due to its own weight is $x \times 10^{-9} m$. The value of $x$ is
(Given. Young's modulus $Y =2 \times 10^{11} Nm ^{-2}$ અને $\left.g=10\, ms ^{-2}\right)$
Overall changes in volume and radii of a uniform cylindrical steel wire are $0.2 \%$ and $0.002 \%$ respectively when subjected to some suitable force. Longitudinal tensile stress acting on the wire is ($Y = 2.0 × 10^{11} Nm^{-2}$)
A beam of metal supported at the two ends is loaded at the centre. The depression at the centre is proportional to