Prove that two circles cannot intersect at more than two points.

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(N/A) Assume that two circles intersect at three distinct points,$A$,$B$,and $C$.
Since $A$,$B$,and $C$ are three distinct points,they are non-collinear.
According to the geometric theorem,there is one and only one circle that passes through three non-collinear points.
Therefore,if two circles pass through the same three points $A$,$B$,and $C$,they must be the same circle.
This contradicts the assumption that there are two distinct circles.
Hence,it is impossible for two distinct circles to intersect at more than two points.

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