Prove that the tangents drawn at the ends of a chord of a circle make equal angles with the chord.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Let $PR$ be a chord of a circle. Tangents are drawn at the points $P$ and $R$. Let these tangents meet at a point $T$ outside the circle.
In $\triangle TPR$,$TP = TR$ (tangents drawn from an external point to a circle are equal in length).
Since $TP = TR$,the angles opposite to these sides are equal,i.e.,$\angle TPR = \angle TRP$.
These angles are the angles made by the tangents with the chord $PR$.
Hence,the tangents drawn at the ends of a chord of a circle make equal angles with the chord.

Explore More

Similar Questions

$P$ is a point in the exterior of a circle having centre $O$ and radius $21$. $OP = 25$. $A$ tangent from $P$ touches the circle at $Q$. Find $PQ$.

The tangents drawn from a point $P$ outside $\odot(O, 5)$ touch the circle at $A$ and $B$. If $PA = 8$,then $PB = \ldots$

If $ABCD$ is a cyclic quadrilateral and $m \angle B = 60^{\circ}$,then the measure of $\angle D = \dots$ (in $^{\circ}$)

In $\Delta ABC$,$\angle B$ is a right angle. If $AB = 8$ and $BC = 6$,find the radius of the incircle of $\Delta ABC$.

Difficult
View Solution

In $Fig.$,$PQ$ is a chord of a circle and $PT$ is the tangent at $P$ such that $\angle QPT = 60^{\circ}$. Then $\angle PRQ$ is equal to (in $^{\circ}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo