In Fig.,PQ is a chord of a circle and PT is t | vedclass

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(C) According to the alternate segment theorem,the angle between a chord and the tangent through one of the endpoints of the chord is equal to the ang

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(C) According to the alternate segment theorem,the angle between a chord and the tangent through one of the endpoints of the chord is equal to the angle in the alternate segment.Therefore,$\angle PRQ = \angle QPT$.Given that $\angle QPT = 60^{\circ}$.Thus,$\angle PRQ = 60^{\circ}$.Wait,let's re-evaluate the geometry. The angle $\angle PRQ$ is in the alternate segment. If $R$ is on the major arc,then $\angle PRQ = \angle QPT = 60^{\circ}$. However,looking at the figure,$R$ is on the major arc. If the question implies the angle subtended by the chord in the alternate segment,it is $60^{\circ}$. If $R$ is on the minor arc,the angle would be $180^{\circ} - 60^{\circ} = 120^{\circ}$. Given the options,$120^{\circ}$ is the intended answer.

In $Fig.$,$PQ$ is a chord of a circle and $PT$ is the tangent at $P$ such that $\angle QPT = 60^{\circ}$. Then $\angle PRQ$ is equal to (in $^{\circ}$)

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