Prove that $(1^{3}+2^{3}+3^{3}+4^{3}+5^{3})^{\frac{1}{2}} = (1^{3}+2^{3}+3^{3}+4^{3})^{\frac{1}{2}} + (5^{3})^{\frac{1}{3}}$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Step $1$: Calculate the sum inside the parentheses on the Left Hand Side $(LHS)$:
$1^{3} + 2^{3} + 3^{3} + 4^{3} + 5^{3} = 1 + 8 + 27 + 64 + 125 = 225$.
Step $2$: Evaluate the $LHS$:
$(225)^{\frac{1}{2}} = \sqrt{225} = 15$.
Step $3$: Calculate the sum inside the first parentheses on the Right Hand Side $(RHS)$:
$1^{3} + 2^{3} + 3^{3} + 4^{3} = 1 + 8 + 27 + 64 = 100$.
Step $4$: Evaluate the $RHS$:
$(100)^{\frac{1}{2}} + (5^{3})^{\frac{1}{3}} = \sqrt{100} + 5^{(3 \times \frac{1}{3})} = 10 + 5^{1} = 10 + 5 = 15$.
Step $5$: Since $LHS = 15$ and $RHS = 15$,the equation is proven.

Explore More

Similar Questions

Express $0.\overline{83}$ in the form $\frac{p}{q}$, where $p$ and $q$ are integers and $q \neq 0$.

Is $0.3\overline{7}$ a rational number or an irrational number?

Simplify: $\left[5\left(8^{\frac{1}{3}}+27^{\frac{1}{3}}\right)^{3}\right]^{\frac{1}{4}}$

Difficult
View Solution

Convert the following rational number into decimal form and state the kind of its decimal expansion: $\frac{37}{60}$

Express $1.23\overline{4}$ in the form $\frac{p}{q}$,where $p$ and $q$ are integers and $q \neq 0$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo