The product of the rearrangement of the given oxyallyl cation is:

Arrange the following carbanions in the order of their stability:
$i$. $RC \equiv C^{\ominus}$
$ii$. $C_6H_5^{\ominus}$
$iii$. $R_2C = CH^{\ominus}$
$iv$. $R_3C - CH_2^{\ominus}$

Which of the following compounds gives the same carbocation on ionization?

Find the correct stability order for the following carbocations:

The increasing order of stability of the following free radicals is:

Arrange the following carbocations in the increasing order of stability with respect to their labels:

Label	Carbocation
$1$	$CH_3-CH^+-CH_3$
$2$	$CH_3^+$
$3$	$(CH_3)_3C^+$
$4$	$CH_3-CH_2^+$