The increasing order of stability of the foll | vedclass

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(B) The stability of free radicals is governed by resonance and inductive effects.$1$. Resonance stabilization: The triphenylmethyl radical $(C_6H_5)_

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$(CH_3)_2\dot{C}H < (CH_3)_3\dot{C} < (C_6H_5)_2\dot{C}H < (C_6H_5)_3\dot{C}$

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(B) The stability of free radicals is governed by resonance and inductive effects.$1$. Resonance stabilization: The triphenylmethyl radical $(C_6H_5)_3\dot{C}$ is more stable than the diphenylmethyl radical $(C_6H_5)_2\dot{C}H$ because it has more phenyl groups to delocalize the unpaired electron.$2$. Inductive effect: Alkyl radicals are stabilized by the $+I$ effect of alkyl groups. The tertiary butyl radical $(CH_3)_3\dot{C}$ is more stable than the isopropyl radical $(CH_3)_2\dot{C}H$.$3$. Overall order: Resonance-stabilized radicals are significantly more stable than alkyl radicals.Therefore,the increasing order of stability is: $(CH_3)_2\dot{C}H < (CH_3)_3\dot{C} < (C_6H_5)_2\dot{C}H < (C_6H_5)_3\dot{C}$.

The increasing order of stability of the following free radicals is:

Similar Questions

The species $A$,$B$,$C$,$D$ formed in the following bond cleavages respectively are:

The decreasing order of hydride affinity for the following carbocations is:
$A: CH_2=CH-C^+(CH_3)_2$
$B: (C_6H_5)_3C^+$
$C: (CH_3)_3C^+$
$D: (Cyclopropyl)_3C^+$
Choose the correct answer from the options given below:

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$ii$. $C_6H_5^{\ominus}$
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$iv$. $R_3C - CH_2^{\ominus}$

Which of the following carbanions is most stable?

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