Which of the following compounds gives the sa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Upon ionization,the $Br^-$ ion leaves,generating a carbocation at the carbon atom previously bonded to the bromine.Compound $1$ is $3$-bromo$-2-$e

Vedclass · Accepted Answer

$1$ and $2$

Vedclass · Answer

(C) Upon ionization,the $Br^-$ ion leaves,generating a carbocation at the carbon atom previously bonded to the bromine.Compound $1$ is $3$-bromo$-2-$ethylbut$-1-$ene. Ionization gives a secondary allylic carbocation: $CH_3-CH^+-C(=CH_2)-CH_2-CH_3$.Compound $2$ is $1$-bromo$-2-$ethylbut$-2-$ene. Ionization gives a primary allylic carbocation: $CH_3-CH=C(CH_2CH_3)-CH_2^+$.These two carbocations are resonance structures of each other,meaning they represent the same delocalized allylic system.Therefore,compounds $1$ and $2$ yield the same resonance-stabilized carbocation.

Which of the following compounds gives the same carbocation on ionization?

Similar Questions

For the following radicals,the correct order of their stability is

The orbital picture of a singlet carbene $(:CH_2)$ can be drawn as:

The most stable carbocation among the following is:

Arrange the following free radicals in order of decreasing stability:
$(A)$ Cyclohexyl-CH2-CH2•
$(B)$ Cyclohexyl-$CH$•-CH3
$(C)$ Cyclohexyl=$CH$-CH2•
(Note: The dot represents the radical center.)

The species $A$,$B$,$C$,$D$ formed in the following bond cleavages respectively are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module