The product $(A)$ of the given reaction is:

$A$ colourless substance $'A'$ $(C_6H_7N)$ is sparingly soluble in water and gives a water-soluble compound $'B'$ on treating with mineral acid. On reacting with $CHCl_3$ and alcoholic potash,$'A'$ produces an obnoxious smell due to the formation of compound $'C'$. Reaction of $'A'$ with benzenesulphonyl chloride gives compound $'D'$ which is soluble in alkali. With $NaNO_2$ and $HCl$,$'A'$ forms compound $'E'$ which reacts with phenol in an alkaline medium to give an orange dye $'F'$. Identify compounds $'A'$ to $'F'$.

Among the compounds given below,the order of basicity is:
$(I)$ Piperidine
$(II)$ Pyridine
$(III)$ Morpholine
$(IV)$ Pyrrole

Which of the following compounds can form alcohol with $NaNO_2/HCl$?

Give the structures of $A$,$B$ and $C$ in the following reactions:
$(i)$ $CH_3CH_2I$ $\xrightarrow{NaCN} A$ $\xrightarrow[Partial\,hydrolysis]{OH^{-}} B$ $\xrightarrow{NaOH+Br_2} C$
$(ii)$ $C_6H_5N_2Cl$ $\xrightarrow{CuCN} A$ $\xrightarrow{H_2O/H^{+}} B$ $\xrightarrow[\Delta]{NH_3} C$
$(iii)$ $CH_3CH_2Br$ $\xrightarrow{KCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow[0\ ^oC]{HNO_2} C$
$(iv)$ $C_6H_5NO_2$ $\xrightarrow{Fe/HCl} A$ $\xrightarrow[273\ K]{NaNO_2+HCl} B$ $\xrightarrow[\Delta]{H_2O/H^{+}} C$
$(v)$ $CH_3COOH$ $\xrightarrow[\Delta]{NH_3} A$ $\xrightarrow{NaOBr} B$ $\xrightarrow{NaNO_2/HCl} C$
$(vi)$ $C_6H_5NO_2$ $\xrightarrow{Fe/HCl} A$ $\xrightarrow[273\ K]{HNO_2} B$ $\xrightarrow{C_6H_5OH} C$

How will you convert:
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?