How will you convert:
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?
(N/A) $(i)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline.
$(ii)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline $\xrightarrow{2CH_3Cl}$ $N,N$-Dimethylaniline.
$(iii)$ $Cl-(CH_2)_4-Cl$ $\xrightarrow{Ethanolic NaCN}$ $NC-(CH_2)_4-CN$ $\xrightarrow{H_2/Ni}$ $H_2N-(CH_2)_6-NH_2$ (Hexane-$1,6$-diamine).
$(ii)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline $\xrightarrow{2CH_3Cl}$ $N,N$-Dimethylaniline.
$(iii)$ $Cl-(CH_2)_4-Cl$ $\xrightarrow{Ethanolic NaCN}$ $NC-(CH_2)_4-CN$ $\xrightarrow{H_2/Ni}$ $H_2N-(CH_2)_6-NH_2$ (Hexane-$1,6$-diamine).
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Similar Questions
Product $D$ is:-
Difficult
View SolutionConsider the following reaction sequence starting from $p$-nitrotoluene:
$(i)$ $\text{Sn/HCl; OH}^-$
(ii) $(\text{CH}_3\text{CO})_2\text{O}$
(iii) $\text{Br}_2/\text{AlBr}_3$
(iv) $\text{H}_3\text{O}^+$
When the final product $(P)$ is subjected to Carius analysis using $\text{AgNO}_3$,$1.0 \text{ g}$ of the product $(P)$ will produce . . . . . . $\text{g}$ of the precipitate of $\text{AgBr}$. (Nearest Integer)
(Given: molar mass in $\text{g mol}^{-1}$: $\text{C} = 12, \text{H} = 1, \text{O} = 16, \text{N} = 14, \text{Br} = 80, \text{Ag} = 108$)
$(i)$ $\text{Sn/HCl; OH}^-$
(ii) $(\text{CH}_3\text{CO})_2\text{O}$
(iii) $\text{Br}_2/\text{AlBr}_3$
(iv) $\text{H}_3\text{O}^+$
When the final product $(P)$ is subjected to Carius analysis using $\text{AgNO}_3$,$1.0 \text{ g}$ of the product $(P)$ will produce . . . . . . $\text{g}$ of the precipitate of $\text{AgBr}$. (Nearest Integer)
(Given: molar mass in $\text{g mol}^{-1}$: $\text{C} = 12, \text{H} = 1, \text{O} = 16, \text{N} = 14, \text{Br} = 80, \text{Ag} = 108$)
DifficultJEE MAIN 2026
View SolutionWhich set of products will be obtained in the following reactions?
$RCN \xrightarrow{\text{reduction}} (a)$
$RCN \xrightarrow[(ii) H_2O]{(i) CH_3MgBr} (b)$
$RNC \xrightarrow{\text{hydrolysis}} (c)$
$RNH_2 \xrightarrow{HNO_2} (d)$
$RCN \xrightarrow{\text{reduction}} (a)$
$RCN \xrightarrow[(ii) H_2O]{(i) CH_3MgBr} (b)$
$RNC \xrightarrow{\text{hydrolysis}} (c)$
$RNH_2 \xrightarrow{HNO_2} (d)$
Medium
View SolutionThe product $(A)$ of the given reaction is:
Difficult
View SolutionWhich of the following reactions does $NOT$ yield an amine?
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