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(B) The starting material is cyclohexane$-1,3-$dione,which contains highly acidic $\alpha$-hydrogens at the $C-2$ position (between the two carbonyl g

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(B) The starting material is cyclohexane$-1,3-$dione,which contains highly acidic $\alpha$-hydrogens at the $C-2$ position (between the two carbonyl groups). When treated with a base like $KOH$,the $C-2$ hydrogen is abstracted to form a stable enolate ion. This enolate ion then acts as a nucleophile and attacks the electrophilic carbon of allyl bromide $(CH_2=CH-CH_2-Br)$ via an $S_N2$ mechanism. This results in the alkylation of the $C-2$ position,yielding $2-$allylcyclohexane$-1,3-$dione as the product $(A)$.

The product $(A)$ is:

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