Which one of the following statements is True | vedclass

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Question

(C) The addition of $PhLi$ (a nucleophile) to the double bond involves the formation of a carbanion intermediate.For compound $1$ (fulvene derivative)

Vedclass · Accepted Answer

$PhLi$ reacts readily with $1$ but does not add to $2$

Vedclass · Answer

(C) The addition of $PhLi$ (a nucleophile) to the double bond involves the formation of a carbanion intermediate.For compound $1$ (fulvene derivative),the addition of $PhLi$ leads to a cyclopentadienyl anion,which is aromatic ($6 \pi$ electrons) and thus highly stable.For compound $2$ (heptafulvene derivative),the addition of $PhLi$ leads to a cycloheptatrienyl anion,which is anti-aromatic ($8 \pi$ electrons) and thus highly unstable.Therefore,$PhLi$ reacts readily with $1$ to form a stable aromatic species but does not add to $2$ because it would form a highly unstable anti-aromatic species.

Which one of the following statements is $True$?

Similar Questions

The order of decreasing reactivity in electrophilic addition of the following compounds is
$(I) \, Ph-CH=CH-COOH$
$(II) \, p-NO_2-C_6H_4-CH=CH-COOH$
$(III) \, p-MeO-C_6H_4-CH=CH-COOH$
$(IV) \, p-Cl-C_6H_4-CH=CH-COOH$

Identify the product and the name of the reaction for the following transformation:
$
\begin{array}{c}
\text{Decalin-1-one oxime} \rightarrow{H_2SO_4} \text{Product}
\end{array} $
(The starting material is a ketoxime derived from decalin$-1-$one with a methyl group at the alpha position).

How many transition states and intermediates will be formed during the course of the following reaction?

In a reaction,if half of the double bond is broken and two new bonds are formed,this is a case of

Which of the following orders is correct?

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