The position-time graph of a particle moving | vedclass

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Question

(B) The correct option is $(B)$.$(i)$ From $t=0 \, s$ to $t=2 \, s$,the position $x=0$,so the velocity $v = \frac{dx}{dt} = 0$.$(ii)$ From $t=2 \, s$

Vedclass · Accepted Answer

Velocity of the particle is opposite to acceleration between $t=2 \, s$ to $t=5 \, s$.

Vedclass · Answer

(B) The correct option is $(B)$.$(i)$ From $t=0 \, s$ to $t=2 \, s$,the position $x=0$,so the velocity $v = \frac{dx}{dt} = 0$.$(ii)$ From $t=2 \, s$ to $t=5 \, s$,the slope of the $x-t$ graph is positive (velocity $v > 0$),but the graph is concave downwards,which implies acceleration $a $(iii)$ From $t=5 \, s$ to $t=8 \, s$,the slope of the $x-t$ graph is negative (velocity $v < 0$),and the graph is concave downwards (acceleration $a < 0$). Since both $v$ and $a$ are negative,they are in the same direction.

The position-time graph of a particle moving along a straight line is shown,which is in the form of a semicircle starting from $t=2 \, s$ to $t=8 \, s$. Select the correct statement.

Similar Questions

The figure shows a velocity-time graph of a particle moving along a straight line. The total distance travelled by the particle is ........ $m$.

The graph below shows the velocity versus time graph for a body. Which of the following graphs represents the corresponding acceleration $v/s$ time graph?

The given graph shows the variation of velocity $v$ with displacement $x$. Which one of the graphs given below correctly represents the variation of acceleration $a$ with displacement $x$?

The $v-t$ plot of a moving object is shown in the figure. The average velocity of the object during the first $10$ seconds is...........$m/s$.

Draw the $x-t$ graphs which represent positive,negative,and zero velocity.

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