Phenol reacts with $CHCl_3$ and $NaOH$ (at $340 \ K$) to give

The major product of the following reaction sequence is:
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$

Which of the following is the strongest acid?

Phenol $\xrightarrow[\Delta ]{Zn} A$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl} B$ $\xrightarrow[\Delta ]{KMnO_4/OH^{-}} C$
The product $C$ is

The major products of the following reaction are:

The order of acidic strength of $X, Y$ and $Z$ is:
Phenol reacts with dilute $HNO_3$ to form $X$ ($o$-nitrophenol) and $Y$ ($p$-nitrophenol). Phenol reacts with concentrated $HNO_3$ and $H_2SO_4$ to form $Z$ ($2,4,6$-trinitrophenol or picric acid).