The order of acidic strength of X, Y and Z is | vedclass

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(D) $1$. $X$ is $o$-nitrophenol,$Y$ is $p$-nitrophenol,and $Z$ is $2,4,6$-trinitrophenol (picric acid).$2$. The acidic strength of phenols increases w

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$Z > Y > X$

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(D) $1$. $X$ is $o$-nitrophenol,$Y$ is $p$-nitrophenol,and $Z$ is $2,4,6$-trinitrophenol (picric acid).$2$. The acidic strength of phenols increases with the presence of electron-withdrawing groups $(-NO_2)$ on the benzene ring due to the stabilization of the phenoxide ion.$3$. $Z$ ($2,4,6$-trinitrophenol) has three $-NO_2$ groups,which exert a strong $-I$ and $-M$ effect,making it the most acidic.$4$. Between $X$ ($o$-nitrophenol) and $Y$ ($p$-nitrophenol),$p$-nitrophenol $(Y)$ is more acidic than $o$-nitrophenol $(X)$ because $o$-nitrophenol forms intramolecular hydrogen bonding,which stabilizes the molecule and makes the release of the $H^+$ ion slightly more difficult compared to $p$-nitrophenol.$5$. Therefore,the order of acidic strength is $Z > Y > X$.

The order of acidic strength of $X, Y$ and $Z$ is:
Phenol reacts with dilute $HNO_3$ to form $X$ ($o$-nitrophenol) and $Y$ ($p$-nitrophenol). Phenol reacts with concentrated $HNO_3$ and $H_2SO_4$ to form $Z$ ($2,4,6$-trinitrophenol or picric acid).

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The order of acidic strength of $X, Y$ and $Z$ is:Phenol reacts with dilute $HNO_3$ to form $X$ ($o$-nitrophenol) and $Y$ ($p$-nitrophenol). Phenol reacts with concentrated $HNO_3$ and $H_2SO_4$ to form $Z$ ($2,4,6$-trinitrophenol or picric acid).