The pair of equations 2x + y - 4 = 0 and x + | vedclass

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(C) For a pair of linear equations $a_{1}x + b_{1}y + c_{1} = 0$ and $a_{2}x + b_{2}y + c_{2} = 0$,the condition for a unique solution is $a_{1}/a_{2}

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unique solution

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(C) For a pair of linear equations $a_{1}x + b_{1}y + c_{1} = 0$ and $a_{2}x + b_{2}y + c_{2} = 0$,the condition for a unique solution is $a_{1}/a_{2} 
eq b_{1}/b_{2}$,which is equivalent to $a_{1}b_{2} - a_{2}b_{1} 
eq 0$.Here,$a_{1} = 2, b_{1} = 1, c_{1} = -4$ and $a_{2} = 1, b_{2} = 2, c_{2} = -5$.Calculating the determinant: $a_{1}b_{2} - a_{2}b_{1} = (2)(2) - (1)(1) = 4 - 1 = 3$.Since $3 
eq 0$,the pair of equations has a unique solution.

The pair of equations $2x + y - 4 = 0$ and $x + 2y - 5 = 0$ has........

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