On a square cardboard sheet of area 784 , cm^ | vedclass

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(A) Given, area of square sheet $= 784 \, cm^{2}$.Since, area of square $= (	ext{side})^{2}$, we have $(	ext{side})^{2} = 784$.Therefore, side $= \s

Vedclass · Accepted Answer

$168$

Vedclass · Answer

(A) Given, area of square sheet $= 784 \, cm^{2}$.Since, area of square $= (	ext{side})^{2}$, we have $(	ext{side})^{2} = 784$.Therefore, side $= \sqrt{784} = 28 \, cm$.Since four congruent circular plates are placed such that each touches the other two and the sides of the square, the diameter of each circular plate is half the side of the square.Diameter of each circular plate $= 28 / 2 = 14 \, cm$.Radius of each circular plate $(r) = 14 / 2 = 7 \, cm$.Area of one circular plate $= \pi r^{2} = \frac{22}{7} 	imes (7)^{2} = 22 	imes 7 = 154 \, cm^{2}$.Area of four circular plates $= 4 	imes 154 = 616 \, cm^{2}$.Area of the square sheet not covered by the circular plates $= 	ext{Area of square} - 	ext{Area of four circular plates}$.$= 784 - 616 = 168 \, cm^{2}$.

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