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(B) Let the third number be $x$.According to the problem, the second number is thrice the third, so the second number $= 3x$.The second number is also

Vedclass · Accepted Answer

$72$

Vedclass · Answer

(B) Let the third number be $x$.According to the problem, the second number is thrice the third, so the second number $= 3x$.The second number is also twice the first, so $2 	imes (	ext{first number}) = 3x$, which means the first number $= \frac{3x}{2}$.The average of the three numbers is given as $44$, so their sum is $44 	imes 3 = 132$.Therefore, $x + 3x + \frac{3x}{2} = 132$.Multiplying by $2$ to clear the fraction: $2x + 6x + 3x = 264$.$11x = 264$, which gives $x = 24$.The three numbers are:First number $= \frac{3(24)}{2} = 36$.Second number $= 3(24) = 72$.Third number $= 24$.The largest number is $72$.

Of the three numbers, the second is twice the first and thrice the third. If the average of the three numbers is $44$, then the largest number is

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