The average of 7 consecutive numbers is 20. T | vedclass

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Question

(C) Let the $7$ consecutive numbers be $x, (x+1), (x+2), (x+3), (x+4), (x+5),$ and $(x+6)$.The average of these numbers is given by the sum divided by

Vedclass · Accepted Answer

$23$

Vedclass · Answer

(C) Let the $7$ consecutive numbers be $x, (x+1), (x+2), (x+3), (x+4), (x+5),$ and $(x+6)$.The average of these numbers is given by the sum divided by the count:$	ext{Average} = \frac{x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6)}{7} = \frac{7x + 21}{7} = x + 3$.Given that the average is $20$,we have:$x + 3 = 20$$x = 20 - 3 = 17$.The largest number is $(x + 6)$.Substituting $x = 17$,we get:$	ext{Largest number} = 17 + 6 = 23$.

The average of $7$ consecutive numbers is $20$. The largest of these numbers is

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