The average of three numbers is 135. The larg | vedclass

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(B) Let the three numbers be $A, B,$ and $C$,where $A$ is the largest number.Given that the average of the three numbers is $135$,their sum is $135

Vedclass · Accepted Answer

$95$

Vedclass · Answer

(B) Let the three numbers be $A, B,$ and $C$,where $A$ is the largest number.Given that the average of the three numbers is $135$,their sum is $135 	imes 3 = 405$.Since the largest number $A = 195$,the sum of the other two numbers is $B + C = 405 - 195 = 210$ $(i)$.We are also given that the difference between the other two numbers is $20$,so $B - C = 20$ $(ii)$.Adding equations $(i)$ and $(ii)$:$(B + C) + (B - C) = 210 + 20$$2B = 230$$B = 115$.Substituting $B = 115$ into equation $(i)$:$115 + C = 210$$C = 210 - 115 = 95$.The three numbers are $195, 115,$ and $95$. Therefore,the smallest number is $95$.

The average of three numbers is $135$. The largest number is $195$ and the difference between the other two is $20$. The smallest number is:

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