Of the species,NO,NO^{+},NO^{2+},NO^{-},the o | vedclass

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Question

(A) The bond strength is directly proportional to the bond order of the species.Total electrons in $NO^{2+}$ = $7 + 8 - 2 = 13$. Bond order = $\frac{1

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$NO^{2+}$

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(A) The bond strength is directly proportional to the bond order of the species.Total electrons in $NO^{2+}$ = $7 + 8 - 2 = 13$. Bond order = $\frac{1}{2}(10 - 3) = 3.5$ (Correction: $NO^{2+}$ has $13$ electrons,configuration $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^1$. Bond order = $\frac{1}{2}(8 - 5) = 1.5$).Total electrons in $NO^{+}$ = $7 + 8 - 1 = 14$. Bond order = $\frac{1}{2}(10 - 4) = 3$.Total electrons in $NO$ = $7 + 8 = 15$. Bond order = $\frac{1}{2}(10 - 5) = 2.5$.Total electrons in $NO^{-}$ = $7 + 8 + 1 = 16$. Bond order = $\frac{1}{2}(10 - 6) = 2$.Comparing the bond orders: $NO^{+} (3) > NO (2.5) > NO^{-} (2) > NO^{2+} (1.5)$.Therefore,$NO^{2+}$ has the minimum bond strength.

Of the species,$NO$,$NO^{+}$,$NO^{2+}$,$NO^{-}$,the one with minimum bond strength is:

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