The sigma _{2s}^* molecular orbital has a nod | vedclass

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(B) The $\sigma _{2s}^*$ molecular orbital is an antibonding molecular orbital formed by the out-of-phase combination of two $2s$ atomic orbitals.It p

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$p$

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(B) The $\sigma _{2s}^*$ molecular orbital is an antibonding molecular orbital formed by the out-of-phase combination of two $2s$ atomic orbitals.It possesses a nodal plane perpendicular to the internuclear axis,which is a characteristic feature of $p$ orbitals (specifically $p_x$ or $p_y$ orbitals depending on the internuclear axis).Therefore,the nodal structure of the $\sigma _{2s}^*$ orbital is similar to that of a $p$ orbital.

List-$I$	List-$II$
$(a)$ $Ne_2$	$(i)$ $1$
$(b)$ $N_2$	$(ii)$ $2$
$(c)$ $F_2$	$(iii)$ $0$
$(d)$ $O_2$	$(iv)$ $3$

The $\sigma _{2s}^*$ molecular orbital has a nodal plane similar to which of the following orbitals?

Similar Questions

When $N_2$ goes to $N_2^+$, the $N-N$ bond distance ..... and when $O_2$ goes to $O_2^+$, the $O-O$ bond distance .......

Match List-$I$ with List-$II$ based on the bond order of the molecules.

List-$I$ List-$II$

$(a)$ $Ne_2$ $(i)$ $1$

$(b)$ $N_2$ $(ii)$ $2$

$(c)$ $F_2$ $(iii)$ $0$

$(d)$ $O_2$ $(iv)$ $3$

Choose the correct answer from the options given below:

When two atomic orbitals combine,they form:

The internuclear distances in $O-O$ bonds for $O_2^+$,$O_2$,$O_2^-$ and $O_2^{2-}$ respectively are

Among the following,the paramagnetic compound is

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