Molecular shapes of $SF_4$,$CF_4$,and $XeF_4$ are
- Athe same with $2, 0$ and $1$ lone pair of electrons respectively
- Bthe same,with $1, 1$ and $1$ lone pair of electrons,respectively
- Cdifferent,with $0, 1$ and $2$ lone pair of electrons,respectively
- Ddifferent with $1, 0$ and $2$ lone pair of electrons,respectively
Explore More
Similar Questions
How many bonding and lone pairs of electrons are present in the structure of ammonia $(NH_3)$?
Easy
View SolutionWhat is the shape of bromine pentafluoride?
Match List-$I$ with List-$II$ and select the correct answer:
List-$I$ (species) List-$II$ ($O-N-O$ angle) $A$. $NO_2^+$ $1$. $180^{\circ}$ $B$. $NO_2$ $2$. $132^{\circ}$ $C$. $NO_2^-$ $3$. $115^{\circ}$ $D$. $NO_3^-$ $4$. $120^{\circ}$
| List-$I$ (species) | List-$II$ ($O-N-O$ angle) |
| $A$. $NO_2^+$ | $1$. $180^{\circ}$ |
| $B$. $NO_2$ | $2$. $132^{\circ}$ |
| $C$. $NO_2^-$ | $3$. $115^{\circ}$ |
| $D$. $NO_3^-$ | $4$. $120^{\circ}$ |
Medium
View SolutionThe shape of $XeF_{5}^{-}$ will be
Match the following:
List-$I$ (Molecule) List-$II$ (Shape) $A$. $XeF_4$ $I$. Square pyramidal $B$. $ClF_3$ $II$. Pentagonal bipyramidal $C$. $BrF_5$ $III$. Square planar $D$. $IF_7$ $IV$. Bent $T$-shape
| List-$I$ (Molecule) | List-$II$ (Shape) |
|---|---|
| $A$. $XeF_4$ | $I$. Square pyramidal |
| $B$. $ClF_3$ | $II$. Pentagonal bipyramidal |
| $C$. $BrF_5$ | $III$. Square planar |
| $D$. $IF_7$ | $IV$. Bent $T$-shape |
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo