Match List-I with List-II and select the corr | vedclass

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Question

(A) $NO_2^+$: $sp$ hybridized,linear geometry,bond angle = $180^{\circ}$.$NO_2$: Bent geometry,bond angle = $132^{\circ}$.$NO_2^-$: $sp^2$ hybridized,

Vedclass · Accepted Answer

$A-1, B-2, C-3, D-4$

Vedclass · Answer

(A) $NO_2^+$: $sp$ hybridized,linear geometry,bond angle = $180^{\circ}$.$NO_2$: Bent geometry,bond angle = $132^{\circ}$.$NO_2^-$: $sp^2$ hybridized,bent geometry,bond angle $\approx 115^{\circ}$ due to lone pair-bond pair repulsion.$NO_3^-$: $sp^2$ hybridized,trigonal planar geometry,bond angle = $120^{\circ}$.Therefore,the correct matching is $A-1, B-2, C-3, D-4$.

List-$I$ (species)	List-$II$ ($O-N-O$ angle)
$A$. $NO_2^+$	$1$. $180^{\circ}$
$B$. $NO_2$	$2$. $132^{\circ}$
$C$. $NO_2^-$	$3$. $115^{\circ}$
$D$. $NO_3^-$	$4$. $120^{\circ}$

Match List-$I$ with List-$II$ and select the correct answer:

List-$I$ (species) List-$II$ ($O-N-O$ angle)

$A$. $NO_2^+$ $1$. $180^{\circ}$

$B$. $NO_2$ $2$. $132^{\circ}$

$C$. $NO_2^-$ $3$. $115^{\circ}$

$D$. $NO_3^-$ $4$. $120^{\circ}$

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Match List-$I$ with List-$II$ and select the correct answer: List-$I$ (species) List-$II$ ($O-N-O$ angle) $A$. $NO_2^+$ $1$. $180^{\circ}$ $B$. $NO_2$ $2$. $132^{\circ}$ $C$. $NO_2^-$ $3$. $115^{\circ}$ $D$. $NO_3^-$ $4$. $120^{\circ}$