Match the following: List-I (Molecule) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $XeF_4$: Central atom $Xe$ has $4$ bond pairs and $2$ lone pairs,resulting in square planar geometry $(III)$.$ClF_3$: Central atom $Cl$ has $3$ bo

Vedclass · Accepted Answer

$A-III, B-IV, C-I, D-II$

Vedclass · Answer

(A) $XeF_4$: Central atom $Xe$ has $4$ bond pairs and $2$ lone pairs,resulting in square planar geometry $(III)$.$ClF_3$: Central atom $Cl$ has $3$ bond pairs and $2$ lone pairs,resulting in bent $T$-shape geometry $(IV)$.$BrF_5$: Central atom $Br$ has $5$ bond pairs and $1$ lone pair,resulting in square pyramidal geometry $(I)$.$IF_7$: Central atom $I$ has $7$ bond pairs and $0$ lone pairs,resulting in pentagonal bipyramidal geometry $(II)$.Therefore,the correct match is $A-III, B-IV, C-I, D-II$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $XeF_4$	$I$. Square pyramidal
$B$. $ClF_3$	$II$. Pentagonal bipyramidal
$C$. $BrF_5$	$III$. Square planar
$D$. $IF_7$	$IV$. Bent $T$-shape

Match the following:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $XeF_4$ $I$. Square pyramidal

$B$. $ClF_3$ $II$. Pentagonal bipyramidal

$C$. $BrF_5$ $III$. Square planar

$D$. $IF_7$ $IV$. Bent $T$-shape

Similar Questions

$XH_3 + H^{+} \longrightarrow XH_4^{+} (X = N, P, As, Sb)$. In this process,the maximum increase in bond angle will be in the case of $:-$

Which of the following species has tetrahedral geometry?

Which compound has a bond angle nearly equal to $90^\circ$?

Which of the following species are isostructural,planar,and non-polar?

The correct structure of $PCl_3F_2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the following: List-$I$ (Molecule) List-$II$ (Shape) $A$. $XeF_4$ $I$. Square pyramidal $B$. $ClF_3$ $II$. Pentagonal bipyramidal $C$. $BrF_5$ $III$. Square planar $D$. $IF_7$ $IV$. Bent $T$-shape