Which of the following 0.1 M solutions will | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The depression in freezing point is a colligative property,which depends on the number of particles in the solution. The formula is $\Delta T_f =

Vedclass · Accepted Answer

Potassium sulphate

Vedclass · Answer

(A) The depression in freezing point is a colligative property,which depends on the number of particles in the solution. The formula is $\Delta T_f = i 	imes K_f 	imes m$. For a given concentration $(m = 0.1 \ M)$,the solution with the highest van't Hoff factor $(i)$ will show the maximum depression in freezing point,resulting in the minimum freezing point. $1.$ Potassium sulphate $(K_2SO_4)$: $i = 3$ $(2K^+ + SO_4^{2-})$. $2.$ Sodium chloride $(NaCl)$: $i = 2$ $(Na^+ + Cl^-)$. $3.$ Urea $(NH_2CONH_2)$: $i = 1$ (non-electrolyte). $4.$ Glucose $(C_6H_{12}O_6)$: $i = 1$ (non-electrolyte). Since $K_2SO_4$ has the highest $i$ value,it will show the maximum depression in freezing point,hence the minimum freezing point.

Which of the following $0.1 \ M$ solutions will exhibit the minimum freezing point?

Similar Questions

Solutions $A$,$B$,$C$ and $D$ are respectively $0.1 \ M$ glucose,$0.05 \ M \ NaCl$,$0.05 \ M \ BaCl_{2}$ and $0.1 \ M \ AlCl_{3}$. Which one of the following pairs is isotonic?

The freezing points of equimolar solutions of glucose,$KNO_3$ and $AlCl_3$ are in the order of:

Observe the following statements:
Statement-$I$: The boiling point of $0.1 \ M$ urea solution is less than that of $0.1 \ M$ $KCl$ solution.
Statement-$II$: Elevation of boiling point is inversely proportional to molar mass of solute.
The correct answer is:

$A$ $0.5 \ m$ aqueous solution of a weak acid $(HX)$ is $20\%$ ionized. If $K_f$ for the solvent is $1.86 \ K \ kg \ mol^{-1}$,the depression in freezing point of the solution is ..... $K$.

The van't Hoff factor $(i)$ for a dilute aqueous solution of the strong electrolyte barium hydroxide is

Vedclass Test Series

Exam Paper Generator

Online Exam Module