The minimum de-Broglie wavelength is associat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The de-Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$.Assuming the same velocity $v$ for all particles,the wavelength is inve

Vedclass · Accepted Answer

$SO_2$ molecule

Vedclass · Answer

(D) The de-Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$.Assuming the same velocity $v$ for all particles,the wavelength is inversely proportional to the mass,i.e.,$\lambda \propto \frac{1}{m}$.Comparing the masses: $m(	ext{electron}) Since the $SO_2$ molecule has the highest molecular mass $(64 \ g/mol)$,it will have the minimum de-Broglie wavelength.Therefore,the correct option is $D$.

The minimum de-Broglie wavelength is associated with which of the following?

Similar Questions

What will be the wavelength of a ball of mass $0.1 \,kg$ moving with a velocity of $10 \,m \,s^{-1}?$

How fast is an electron moving if it has a wavelength equal to the distance it travels in one second?

Given the ratio of kinetic energy of an electron in two orbitals is $16:9$. Calculate the ratio of the wavelength of the electron waves.

The kinetic energy of an electron is $4.55 \times 10^{-25} \ J$. Find its wavelength.

Dual nature of particles was proposed by

Vedclass Test Series

Exam Paper Generator

Online Exam Module