The mean kinetic energy per degree of freedom of gas molecules is:

  • A
    $\frac{3}{2}k_BT$
  • B
    $k_BT$
  • C
    $\frac{1}{2}k_BT$
  • D
    $\frac{3}{2}RT$

Explore More

Similar Questions

The number of rotational degrees of freedom of a monatomic molecule is

$A$ diatomic gas consisting of rigid molecules is at a temperature of $87^{\circ} C$. If the moment of inertia of the rotating diatomic rigid molecule is $2.76 \times 10^{-39} \text{ g cm}^2$,then the rms angular speed of the molecule is (Boltzmann constant $= 1.38 \times 10^{-23} \text{ J K}^{-1}$).

$A$ diatomic molecule has how many degrees of freedom?

How many degrees of freedom does a diatomic gas have due to its translational motion?

Write the degree of freedom for a polyatomic gas.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo