A diatomic molecule has how many degrees of f | vedclass

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(C) The number of degrees of freedom $f$ for a molecule is given by the formula $f = 3N - k$,where $N$ is the number of atoms and $k$ is the number of

Vedclass · Accepted Answer

$5$

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(C) The number of degrees of freedom $f$ for a molecule is given by the formula $f = 3N - k$,where $N$ is the number of atoms and $k$ is the number of constraints.For a rigid diatomic molecule,there are $N = 2$ atoms and $k = 1$ constraint (the fixed distance between the atoms).Substituting these values,we get $f = 3(2) - 1 = 5$.Thus,a diatomic molecule has $5$ degrees of freedom ($3$ translational and $2$ rotational).

$A$ diatomic molecule has how many degrees of freedom?

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