Class 11PhysicsKinetic Theory of GasesMolar Specific Heat of gas and relation between them (Mayer's formula)
EasyMatch the following ( $f$ is number of degrees of freedom):
Gases
$C_P/C_V$ value
$A$
Monoatomic
$I$
$(4+f)/(3+f)$
$B$
Diatomic (rigid)
$II$
$5/3$
$C$
Diatomic (non-rigid)
$III$
$7/5$
$D$
Polyatomic
$IV$
$9/7$
| Gases | $C_P/C_V$ value | ||
|---|---|---|---|
| $A$ | Monoatomic | $I$ | $(4+f)/(3+f)$ |
| $B$ | Diatomic (rigid) | $II$ | $5/3$ |
| $C$ | Diatomic (non-rigid) | $III$ | $7/5$ |
| $D$ | Polyatomic | $IV$ | $9/7$ |
- A$A-II, B-III, C-IV, D-I$
- B$A-II, B-I, C-III, D-IV$
- C$A-IV, B-III, C-I, D-II$
- D$A-II, B-III, C-IV, D-I$
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View SolutionLet $\gamma_1$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $\gamma_2$ be the similar ratio of a diatomic gas. Considering the diatomic gas molecule as a rigid rotator,the ratio $\frac{\gamma_1}{\gamma_2}$ is
If the degree of freedom of a gas is $f,$ then the ratio of two specific heats ${C_P}/{C_V}$ is given by
Match the List-$I$ with List-$II$:
List-$I$ List-$II$ $A$. Triatomic rigid gas $I$. $\frac{C_P}{C_V} = \frac{5}{3}$ $B$. Diatomic non-rigid gas $II$. $\frac{C_P}{C_V} = \frac{7}{5}$ $C$. Monoatomic gas $III$. $\frac{C_P}{C_V} = \frac{4}{3}$ $D$. Diatomic rigid gas $IV$. $\frac{C_P}{C_V} = \frac{9}{7}$
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| $A$. Triatomic rigid gas | $I$. $\frac{C_P}{C_V} = \frac{5}{3}$ |
| $B$. Diatomic non-rigid gas | $II$. $\frac{C_P}{C_V} = \frac{7}{5}$ |
| $C$. Monoatomic gas | $III$. $\frac{C_P}{C_V} = \frac{4}{3}$ |
| $D$. Diatomic rigid gas | $IV$. $\frac{C_P}{C_V} = \frac{9}{7}$ |
Choose the correct answer from the options given below:
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