Class 11PhysicsKinetic Theory of GasesMolar Specific Heat of gas and relation between them (Mayer's formula)
MediumLet $\gamma_1$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $\gamma_2$ be the similar ratio of a diatomic gas. Considering the diatomic gas molecule as a rigid rotator,the ratio $\frac{\gamma_1}{\gamma_2}$ is
- A$\frac{27}{35}$
- B$\frac{35}{27}$
- C$\frac{25}{21}$
- D$\frac{21}{25}$
Explore More
Similar Questions
For hydrogen gas $C_p - C_v = a$ and for oxygen gas $C_p - C_v = b$. The relation between $a$ and $b$ is given by:
When heat is supplied to a diatomic gas,it expands at constant pressure. What fraction of the heat supplied is converted into internal energy?
Medium
View SolutionThe ratio of the specific heats $\frac{C_{p}}{C_{v}}=\gamma$ in terms of degrees of freedom $n$ is given by
For a gas,$\frac{R}{C_{v}} = 0.67$. This gas is made up of molecules which are
Match the $\frac{C_{P}}{C_{v}}$ ratio for ideal gases with different types of molecules:
Molecule type $\frac{C_{P}}{C_{v}}$ $A$. Monoatomic $I$. $\frac{7}{5}$ $B$. Diatomic rigid molecules $II$. $\frac{9}{7}$ $C$. Diatomic non-rigid molecules $III$. $\frac{4}{3}$ $D$. Triatomic rigid molecules $IV$. $\frac{5}{3}$
| Molecule type | $\frac{C_{P}}{C_{v}}$ |
|---|---|
| $A$. Monoatomic | $I$. $\frac{7}{5}$ |
| $B$. Diatomic rigid molecules | $II$. $\frac{9}{7}$ |
| $C$. Diatomic non-rigid molecules | $III$. $\frac{4}{3}$ |
| $D$. Triatomic rigid molecules | $IV$. $\frac{5}{3}$ |
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo