Mass numbers of the elements A, B, C and D ar | vedclass

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Question

(B) Energy released in a nuclear reaction is given by $\Delta E = E_{	ext{final}} - E_{	ext{initial}}$,where $E = 	ext{Mass Number} 	imes 	ext{Sp

Vedclass · Accepted Answer

Only in $(1)$

Vedclass · Answer

(B) Energy released in a nuclear reaction is given by $\Delta E = E_{	ext{final}} - E_{	ext{initial}}$,where $E = 	ext{Mass Number} 	imes 	ext{Specific Binding Energy}$.For reaction $(1): D ightarrow 2B$$\Delta E = (2 	imes 60 	imes 8.5) - (120 	imes 7) = 1020 - 840 = +180 	ext{ MeV}$. (Energy is released)For reaction $(2): C ightarrow B + A$$\Delta E = (60 	imes 8.5 + 30 	imes 5) - (90 	imes 8) = (510 + 150) - 720 = 660 - 720 = -60 	ext{ MeV}$. (Energy is absorbed)For reaction $(3): B ightarrow 2A$$\Delta E = (2 	imes 30 	imes 5) - (60 	imes 8.5) = 300 - 510 = -210 	ext{ MeV}$. (Energy is absorbed)Thus,energy is released only in reaction $(1)$.

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