The binding energy per nucleon of { }_{8}^{16 | vedclass

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(C) The reaction for removing one neutron from ${ }_{8}^{17}O$ is given by: ${ }_{8}^{17}O \rightarrow { }_{8}^{16}O + { }_{0}^{1}n$.To find the energ

Vedclass · Accepted Answer

$4.23$

Vedclass · Answer

(C) The reaction for removing one neutron from ${ }_{8}^{17}O$ is given by: ${ }_{8}^{17}O ightarrow { }_{8}^{16}O + { }_{0}^{1}n$.To find the energy required,we calculate the difference between the total binding energy of the products and the reactant.Total binding energy of ${ }_{8}^{17}O = 17 	imes 7.75 	ext{ MeV} = 131.75 	ext{ MeV}$.Total binding energy of ${ }_{8}^{16}O = 16 	imes 7.97 	ext{ MeV} = 127.52 	ext{ MeV}$.The energy required to remove the neutron is the difference in total binding energies:$E = 131.75 	ext{ MeV} - 127.52 	ext{ MeV} = 4.23 	ext{ MeV}$.

The binding energy per nucleon of ${ }_{8}^{16}O$ is $7.97 \text{ MeV}$ and that of ${ }_{8}^{17}O$ is $7.75 \text{ MeV}$. The energy required to remove one neutron from ${ }_{8}^{17}O$ is $\qquad \text{ MeV}$.

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