If the binding energy of the deuterium is $2.23 \, MeV$, the mass defect in $a.m.u.$ is:

The binding energy per nucleon versus mass number curve for nuclei is shown in the figure. $W, X, Y$ and $Z$ are four nuclei indicated on the curve. The process that would release energy is

Two nuclei of mass number $3$ combine with another nucleus of mass number $4$ to yield a nucleus of mass number $10$. If the binding energy per nucleon for the mass numbers $3$,$4$,and $10$ are $5.6 \text{ MeV}$,$7.4 \text{ MeV}$,and $6.1 \text{ MeV}$,respectively,then in the process,$\Delta Mc^2 = . . . . . . \text{ MeV}$.

What does the binding energy per nucleon show?

$1 \text{ amu}$ is equal to

The masses of neutron,proton and deuteron in amu are $1.00893$,$1.00813$ and $2.01473$,respectively. The packing fraction of the deuteron in amu is