Magnetic fields at two points on the axis of | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $B = \frac{{{\mu _0}}}{{4\pi }} 	imes \frac{{2\pi Ni{R^2}}}{{{{({R^2} + {x^2})}^{3/2}}}} $

$\Rightarrow B \propto \frac{1}{{{{({r^2} + {x^2})}

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(b) $B = \frac{{{\mu _0}}}{{4\pi }} 	imes \frac{{2\pi Ni{R^2}}}{{{{({R^2} + {x^2})}^{3/2}}}} $

$\Rightarrow B \propto \frac{1}{{{{({r^2} + {x^2})}^{3/2}}}}$
$ \Rightarrow \frac{8}{1} = \frac{{{{({R^2} + x_2^2)}^{3/2}}}}{{{{({R^2} + x_1^2)}^{3/2}}}} $

$\Rightarrow {\left( {\frac{8}{1}} ight)^{2/3}} = \frac{{{R^2} + 0.04}}{{{R^2} + 0.0025}}$
$ \Rightarrow \frac{4}{1} = \frac{{{R^2} + 0.04}}{{{R^2} + 0.0025}}$. On solving $R = 0.1\,m$

Magnetic fields at two points on the axis of a circular coil at a distance of $0.05\,m$ and $0.2\,m$ from the centre are in the ratio $8 : 1$. The radius of the coil is.....$m$

Similar Questions

There are two infinitely long straight current carrying conductors and they are held at right angles to each other so that their common ends meet at the origin as shown in the figure given below. The ratio of current in both conductor is $1: 1$. The magnetic field at point $P$ is ...... .

Two circular coils $1$ and $2$ are made from the same wire but the radius of the $1^{st}$ coil is twice that of the $2^{nd}$ coil. What is the ratio of potential difference in volts should be applied across them so that the magnetic field at their centres is the same?

A long insulated copper wire is closely wound as a spiral of ' $N$ ' turns. The spiral has inner radius ' $a$ ' and outer radius ' $b$ '. The spiral lies in the $X-Y$ plane and a steady current ' $I$ ' flows through the wire. The $Z$-component of the magnetic field at the center of the spiral is

A coil of $12$ turns made by a constant length current carrying wire. If number of turns makes $3$ then change in magnetic field produced at its centre