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(C) The ratio of amplitudes is given as $\frac{a_1}{a_2} = \frac{3}{2}$.We know that the intensity $I$ is proportional to the square of the amplitude

Vedclass · Accepted Answer

$25:1$

Vedclass · Answer

(C) The ratio of amplitudes is given as $\frac{a_1}{a_2} = \frac{3}{2}$.We know that the intensity $I$ is proportional to the square of the amplitude $a$,so $I \propto a^2$.The ratio of maximum intensity to minimum intensity in an interference pattern is given by the formula:$\frac{I_{\max}}{I_{\min}} = \left( \frac{a_1 + a_2}{a_1 - a_2} \right)^2$.Dividing the numerator and denominator by $a_2$,we get:$\frac{I_{\max}}{I_{\min}} = \left( \frac{\frac{a_1}{a_2} + 1}{\frac{a_1}{a_2} - 1} \right)^2$.Substituting the given ratio $\frac{a_1}{a_2} = \frac{3}{2}$:$\frac{I_{\max}}{I_{\min}} = \left( \frac{\frac{3}{2} + 1}{\frac{3}{2} - 1} \right)^2 = \left( \frac{\frac{5}{2}}{\frac{1}{2}} \right)^2 = (5)^2 = 25$.Thus,the ratio is $25:1$.

Light waves producing interference have their amplitudes in the ratio $3:2$. The intensity ratio of maximum and minimum of interference fringes is

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