Light waves producing interference have their | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the ratio of amplitudes of two light waves is $\frac{a_1}{a_2} = \frac{3}{2}$.Let $a_1 = 3k$ and $a_2 = 2k$,where $k$ is a constant.The inte

Vedclass · Accepted Answer

$25: 1$

Vedclass · Answer

(C) Given the ratio of amplitudes of two light waves is $\frac{a_1}{a_2} = \frac{3}{2}$.Let $a_1 = 3k$ and $a_2 = 2k$,where $k$ is a constant.The intensity $I$ is proportional to the square of the amplitude,$I \propto a^2$.The ratio of maximum intensity to minimum intensity in an interference pattern is given by the formula:$\frac{I_{\max}}{I_{\min}} = \frac{(a_1 + a_2)^2}{(a_1 - a_2)^2}$.Substituting the values:$\frac{I_{\max}}{I_{\min}} = \frac{(3k + 2k)^2}{(3k - 2k)^2} = \frac{(5k)^2}{(k)^2} = \frac{25k^2}{k^2} = \frac{25}{1}$.Thus,the intensity ratio is $25: 1$.

Light waves producing interference have their amplitudes in the ratio $3: 2$. The intensity ratio of maximum and minimum of interference fringes is

Similar Questions

Which one of the following removes temporary hardness of water?

With a standard rectangular bar magnet,the time period of a vibration magnetometer is $4 ~s$. The bar magnet is cut parallel to its length into four equal pieces. The time period of the vibration magnetometer when one piece is used (in seconds) (bar magnet breadth is small) is

$A$ charged particle moves through a magnetic field in a direction perpendicular to it. Then the

In the Young's double slit experiment using a monochromatic light of wavelength $\lambda$,the path difference (in terms of an integer $n$) corresponding to any point having half the peak intensity is :-

If $\sin ^{-1}\left(\frac{3}{x}\right)+\sin ^{-1}\left(\frac{4}{x}\right)=\frac{\pi}{2}$,then $x$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module