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(B) When a charged particle moves in a magnetic field with velocity $\vec{v}$ perpendicular to the magnetic field $\vec{B}$,the magnetic force acting

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speed of the particle remains unchanged

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(B) When a charged particle moves in a magnetic field with velocity $\vec{v}$ perpendicular to the magnetic field $\vec{B}$,the magnetic force acting on it is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force $\vec{F}$ is always perpendicular to the velocity $\vec{v}$,it does no work on the particle $(W = \vec{F} \cdot \vec{d} = 0)$.According to the work-energy theorem,the change in kinetic energy is zero,which implies that the speed of the particle remains constant.However,because the direction of the force changes as the particle moves,both the velocity vector and the acceleration vector change continuously.

$A$ charged particle moves through a magnetic field in a direction perpendicular to it. Then the

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