Let ${I_1} = \int_a^{\pi - a} {xf(\sin x)dx}$ and ${I_2} = \int_a^{\pi - a} {f(\sin x)dx}$,then ${I_2}$ is equal to

  • A
    $\frac{\pi }{2}{I_1}$
  • B
    $\pi {I_1}$
  • C
    $\frac{2}{\pi }{I_1}$
  • D
    $2{I_1}$

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