Let $z$ be a complex number such that $|z + 2| = |z - 2|$ and $\arg\left(\frac{z + 3}{z - i}\right) = \frac{\pi}{4}$. Then $|z|^2$ is equal to:

  • A
    $9$
  • B
    $4$
  • C
    $5$
  • D
    $1$

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