ધારો કે $A = \{x : |x^{2} - 10| \le 6\}$ અને $B = \{x : |x - 2| > 1\}$. તો:

• A
  $A \cup B = (-\infty, 1) \cup [2, \infty)$
• B
  $A - B = [2, 3]$
• C
  $A \cap B = [-4, -2] \cup (3, 4]$
• D
  $B - A = (-\infty, -4) \cup (-2, 1) \cup (4, \infty)$