Let $[x]$ denote the greatest integer less than or equal to $x$ for any real number $x$. Then,$\lim _{n \rightarrow \infty} \frac{[n \sqrt{2}]}{n}$ is equal to

  • A
    $0$
  • B
    $2$
  • C
    $\sqrt{2}$
  • D
    $1$

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