Let $a_n = (1^2 + 2^2 + \ldots + n^2)^n$ and $b_n = n^n(n!)$. Then

  • A
    $a_n < b_n$ for all $n$
  • B
    $a_n > b_n$ for all $n$
  • C
    $a_n = b_n$ for infinitely many $n$
  • D
    $a_n < b_n$ if $n$ is even and $a_n > b_n$ if $n$ is odd

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