Let $A$ and $B$ be two $3 \times 3$ non-singular matrices such that $\operatorname{det}(A^T B A) = 27$ and $\operatorname{det}(A B^{-1}) = 8$. Then $\operatorname{det}(B^T A^{-1} B) = $

  • A
    $\frac{3}{32}$
  • B
    $\frac{1}{16}$
  • C
    $1$
  • D
    $16$

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