Let A, B and C are the angles of a plain tria | vedclass

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Question

(a) $A + B + C = \pi $ 

$	herefore \,\,\,	an \left( {\frac{{A + B}}{2}} ight) = 	an \left( {\frac{\pi }{2} - \frac{C}{2}} ight)$

Vedclass · Accepted Answer

$7/9$

Vedclass · Answer

(a) $A + B + C = \pi $ 

$	herefore \,\,\,	an \left( {\frac{{A + B}}{2}} ight) = 	an \left( {\frac{\pi }{2} - \frac{C}{2}} ight)$ 

==> $\frac{{	an \frac{A}{2} + 	an \frac{B}{2}}}{{1 - 	an \frac{A}{2}.	an \frac{B}{2}}} = \cot \frac{C}{2} $

$\Rightarrow \frac{{\frac{1}{3} + \frac{2}{3}}}{{1 - \frac{1}{3}.\frac{2}{3}}} = \frac{9}{7} = \cot \frac{C}{2}$ 

$	herefore  \,\,  	an \frac{C}{2} = \frac{7}{9}$.

Let $A, B$ and $C$ are the angles of a plain triangle and $\tan \frac{A}{2} = \frac{1}{3},\,\,\tan \frac{B}{2} = \frac{2}{3}$. Then $\tan \frac{C}{2}$ is equal to

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