Let R = {(1, 3), (4, 2), (2, 4), (2, 3), (3, | vedclass

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(C) Given $A = \{1, 2, 3, 4\}$ and $R = \{(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)\}$.$1$. For $R$ to be symmetric,$(a, b) \in R$ must imply $(b, a) \in

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Not symmetric

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(C) Given $A = \{1, 2, 3, 4\}$ and $R = \{(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)\}$.$1$. For $R$ to be symmetric,$(a, b) \in R$ must imply $(b, a) \in R$. Here,$(2, 3) \in R$ but $(3, 2) 
otin R$. Hence,$R$ is not symmetric.$2$. For $R$ to be reflexive,$(a, a) \in R$ for all $a \in A$. Since $(1, 1) 
otin R$,$R$ is not reflexive.$3$. For $R$ to be a function,each element in $A$ must have a unique image. Here,$2$ is mapped to both $4$ and $3$ (i.e.,$(2, 4) \in R$ and $(2, 3) \in R$),so $R$ is not a function.$4$. For $R$ to be transitive,$(a, b) \in R$ and $(b, c) \in R$ must imply $(a, c) \in R$. Here,$(1, 3) \in R$ and $(3, 1) \in R$,but $(1, 1) 
otin R$. Thus,$R$ is not transitive.Therefore,the correct statement is that $R$ is not symmetric.

Let $R = \{(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)\}$ be a relation on the set $A = \{1, 2, 3, 4\}$. The relation $R$ is

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