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(D) Given sets are:$A = \{2, 4, 6, 8, 10, 12, \dots\}$$B = \{5, 10, 15, 20, 25, \dots\}$$C = \{10, 20, 30, 40, \dots\}$First,find the intersection of

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$C$

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(D) Given sets are:$A = \{2, 4, 6, 8, 10, 12, \dots\}$$B = \{5, 10, 15, 20, 25, \dots\}$$C = \{10, 20, 30, 40, \dots\}$First,find the intersection of $A$ and $B$:$A \cap B$ represents the set of numbers that are multiples of both $2$ and $5$. Since the least common multiple of $2$ and $5$ is $10$,$A \cap B = \{10, 20, 30, \dots\}$.Comparing this with set $C$,we see that $A \cap B = C$.Now,find $(A \cap B) \cap C$:$(A \cap B) \cap C = C \cap C = C$.Therefore,the set $(A \cap B) \cap C$ is equal to $C$.

Let $A = \{x : x \in N \text{ and } x \text{ is a multiple of } 2\}$,$B = \{x : x \in N \text{ and } x \text{ is a multiple of } 5\}$,and $C = \{x : x \in N \text{ and } x \text{ is a multiple of } 10\}$. Describe the set $(A \cap B) \cap C$.

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