If n(A) = 4,n(B) = 3,and n(A times B times C) | vedclass

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(D) Given that $n(A) = 4$,$n(B) = 3$,and $n(A 	imes B 	imes C) = 24$.We know that for the Cartesian product of three sets,the number of elements is

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$2$

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(D) Given that $n(A) = 4$,$n(B) = 3$,and $n(A 	imes B 	imes C) = 24$.We know that for the Cartesian product of three sets,the number of elements is given by $n(A 	imes B 	imes C) = n(A) 	imes n(B) 	imes n(C)$.Substituting the given values into the formula:$4 	imes 3 	imes n(C) = 24$$12 	imes n(C) = 24$$n(C) = \frac{24}{12}$$n(C) = 2$.

If $n(A) = 4$,$n(B) = 3$,and $n(A \times B \times C) = 24$,then $n(C) = $

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